A Problem in Logic (42)

6 Name: #!/usr/bin/anonymous : 2008-05-04 14:14 ID:Heaven

>>5
Ok then, now it makes more sense

tD(a, b, c) =
!(((a & b & c) | b | c) == a)
fE(a, b, c, d) =
tD(a, b, c) == tD(a, b, c) == TRUE

fE returns FALSE if they are all equal and TRUE if they are unequal.

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